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∴ we have \(\frac{\mathrm{AB}}{\mathrm{PQ}}=\frac{\mathrm{AC}}{\mathrm{PR}}=\frac{\mathrm{BC}}{\mathrm{QR}}\)D is the mid-point of BC. BD = DC.M Is the mid-point of QR. QM = MR\(\frac{\mathrm{BC}}{\mathrm{QR}}=\frac{\frac{1}{2}

⇒ cot β + cot γ = \(\frac{\left(u^{2} \sin 2 \alpha\right) / g}{\left(u^{2} \sin ^{2} \alpha\right) / 2 g}\)

Karnataka 1st PUC Physics Question Bank Chapter 5 Laws of Motion 1st PUC Physics Laws of Motion TextBook Questions and

1st PUC Statistics Classification and Tabulation Two Marks Questions and Answers Question 1. What is classification of the data? Solution:

Here = $$\frac{\text { No. of units in the population }}{\text { No. of units in the sample }}$$ For

Are you looking for comprehensive KSEEB 2nd PUC Basic Maths Chapter 21 Definite Integrals and Its Application to Areas Ex

Are you a student in Karnataka looking for comprehensive KSEEB 2nd PUC Basic Maths Chapter 21 Definite Integrals and Its

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